Question

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in a population of pea plants, the gene that determines the pea shape phenotype has two alleles. the allele for round peas (r) is dominant to the allele for wrinkled peas (r). in the same population of pea plants, the gene for pea color also has two alleles. the allele for yellow color (y) is dominant to the allele for green color (y).

a pea plant that is homozygous dominant for pea shape and heterozygous for pea color is crossed with a pea plant that is homozygous recessive for both pea shape and pea color.

what are the possible genotypes of the offspring of this cross?
you may find it useful to use a punnett square to answer this question.

choose 2 answers:

Explanation:

Step1: Determine Parent Genotypes

First, identify the genotypes of the parent plants. The first plant is homozygous dominant for shape (\(RR\)) and heterozygous for color (\(Yy\)), so its genotype is \(RRYy\). The second plant is homozygous recessive for both, so its genotype is \(rryy\).

Step2: Find Gametes

For \(RRYy\), the possible gametes are determined by independent assortment. Since \(RR\) can only contribute \(R\), and \(Yy\) can contribute \(Y\) or \(y\), the gametes are \(RY\) and \(Ry\). For \(rryy\), since both genes are homozygous recessive, it can only produce \(ry\) gametes.

Step3: Construct Punnett Square

Set up the Punnett square with the gametes from each parent. The rows are \(RY\) and \(Ry\) (from \(RRYy\)), and the column is \(ry\) (from \(rryy\)).

• Crossing \(RY\) (row) with \(ry\) (column) gives \(RrYy\).
• Crossing \(Ry\) (row) with \(ry\) (column) gives \(Rryy\).

Answer:

The possible genotypes of the offspring are \(RrYy\) and \(Rryy\). (Note: Since the original question mentions "Choose 2 answers" but the options weren't provided, these are the two genotypes derived from the cross. If there were options, these would match the correct ones among them.)