Question

the point b is plotted on the coordinate grid below. plot the point b, the reflection of b over the y-axis. click on the graph to plot a point. click a point to delete it.

Explanation:

Step1: Identify coordinates of B

First, we determine the coordinates of point \( B \). From the graph, we can see that point \( B \) is at \( (-6, -2) \) (assuming the grid and the position of \( B \) as per the visual; typically, we look at the x - coordinate (horizontal) and y - coordinate (vertical) values. If we move 6 units to the left of the origin on the x - axis (so \( x=-6 \)) and 2 units down on the y - axis (so \( y = - 2\))).

Step2: Apply reflection over y - axis rule

The rule for reflecting a point \( (x,y) \) over the \( y \) - axis is \( (x,y)\to(-x,y) \). So for the point \( B(-6,-2) \), when we reflect it over the \( y \) - axis, we change the sign of the \( x \) - coordinate.

Substitute \( x=-6 \) and \( y = - 2 \) into the reflection rule:
The new \( x \) - coordinate is \( -(-6)=6 \), and the \( y \) - coordinate remains \( -2 \). So the coordinates of \( B' \) are \( (6,-2) \).

To plot \( B' \), we move 6 units to the right on the \( x \) - axis (since \( x = 6\)) and 2 units down on the \( y \) - axis (since \( y=-2 \)) and mark the point.

Answer:

The coordinates of \( B' \) (the reflection of \( B \) over the \( y \) - axis) are \( (6,-2) \), and it should be plotted at the point with \( x = 6 \) and \( y=-2 \) on the coordinate grid.