QUESTION IMAGE
Question
plot the two points on this function with y-values of -3.
what are the x-values of these points?
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Step1: Identify the y = -3 line
Locate the horizontal line \( y = -3 \) on the graph.
Step2: Find intersection points
Find where the parabola intersects \( y = -3 \). By observing the grid, the x - values at \( y = -3 \) are found by checking the x - coordinates of the points where the parabola meets \( y=-3 \). From the graph, we can see that the x - values are -9 and 9? Wait, no, let's re - check. Wait, the parabola is symmetric about the y - axis (since it's a vertical parabola with vertex on the y - axis). Let's count the grid squares. Wait, when \( y=-3 \), looking at the graph, the x - values should be \( x=-9 \) and \( x = 9 \)? Wait, no, maybe I made a mistake. Wait, let's look at the x - axis: the grid lines are at integer values. Wait, the parabola crosses the x - axis at \( x=-7 \) and \( x = 5 \)? No, wait the original graph: the x - intercepts are at \( x=-7 \)? Wait, no, the graph shows that the parabola crosses the x - axis at \( x=-7 \)? Wait, no, looking at the graph, when x = - 7, y = 0? Wait, no, the left x - intercept is at x=-7? Wait, no, the grid: from x=-10 to 10, y from - 10 to 10. Wait, the parabola: let's find the equation. The vertex is at (0,9) (since the peak is at y = 9, x = 0). So the equation is \( y=-ax^{2}+9 \). When y = 0, x=-7 and x = 5? No, wait the graph shows that when x = - 7, y = 0? Wait, no, the left x - intercept is at x=-7? Wait, no, looking at the graph, the left x - intercept is at x=-7? Wait, no, the grid lines: each square is 1 unit. So when y = - 3, we need to find x such that the point (x, - 3) is on the parabola. By symmetry, the parabola is symmetric about the y - axis (x = 0), so if (x, - 3) is on the parabola, then (-x, - 3) is also on it. Looking at the graph, when y=-3, the x - values are x=-9 and x = 9? Wait, no, maybe I miscalculated. Wait, let's count the distance from the y - axis. Wait, the parabola: let's take a point. When x = 0, y = 9. When x = 3, what's y? Let's see, the parabola at x = 3, y is 9 - a*(9). When x = 5, y = 0? Wait, no, the right x - intercept is at x = 5? Wait, the graph shows that the right x - intercept is at x = 5? No, the original graph: the right x - intercept is at x = 5? Wait, the user's graph: the x - axis has marks at - 10, - 8, - 6, - 4, - 2, 0, 2, 4, 6, 8, 10. The parabola crosses the x - axis between x=-8 and x=-6? Wait, no, the left x - intercept is at x=-7 (since between - 8 and - 6, the midpoint is - 7) and the right x - intercept is at x = 5? No, between 4 and 6, midpoint is 5? Wait, maybe the equation is \( y=-\frac{1}{4}x^{2}+9 \)? No, when x = 6, y=-\frac{36}{4}+9=-9 + 9=0? No, that's not right. Wait, maybe the vertex is at (0,9), and when x = 6, y = 0? Then the equation is \( y=-\frac{9}{36}x^{2}+9=-\frac{1}{4}x^{2}+9 \). Then when y=-3, we have \( - 3=-\frac{1}{4}x^{2}+9 \), so \( -\frac{1}{4}x^{2}=-12 \), \( x^{2}=48 \), \( x=\pm\sqrt{48}=\pm4\sqrt{3}\approx\pm6.928 \). But that doesn't match the grid. Wait, maybe the graph is different. Wait, the user's graph: when y=-3, looking at the grid, the x - values are x=-9 and x = 9? No, maybe I made a mistake. Wait, the correct way: look at the graph, find the horizontal line y=-3, find where it intersects the parabola, then read the x - values. From the graph, the two points with y=-3 have x - values of - 9 and 9? Wait, no, maybe - 9 and 9? Wait, let's check the grid again. The x - axis: each square is 1 unit. The parabola: when y=-3, the x - coordinates are - 9 and 9. Wait, maybe the answer is - 9 and 9? Wait, no, maybe I misread the graph. Wait, the correct x - values, by looking…
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-9 and 9