Question

a placekicker for a football team makes field goals 55% of the time when kicking from the 35 - yard line. assume that field goal attempts can be considered random events. using the table, what is the probability that the placekicker will make at least 3 of his next 5 attempts from the 35 - yard line?

0.34
0.26
0.60
0.74

Explanation:

Step1: Understand the meaning of "at least 3"

"At least 3" means 3 or 4 or 5.

Step2: Sum up the probabilities

We know the probabilities for 3, 4, and 5. The probability for 3 is \(0.34\), for 4 is \(0.21\). First, find the probability for 5. Since the sum of all probabilities in a probability distribution is 1. Let \(P(5)=x\). Then \(0.02 + 0.11+0.27 + 0.34+0.21+x=1\).

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Now, \(P(\text{at least 3})=P(3)+P(4)+P(5)\)

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Answer:

0.60