Question

in photosynthesis, carbon dioxide (co₂) and water (h₂o) combine to form the sugar glucose (c₆h₁₂o₆) in the following reaction: 6co₂ + 6h₂o → c₆h₁₂o₆ + ? assuming this equation is balanced, which part is missing from the product side? (1 point) 6 carbon atoms 6 oxygen atoms 12 hydrogen atoms 12 oxygen atoms

Explanation:

Step1: Count C, H, O on reactant side

Reactants: \(6CO_2 + 6H_2O\)

• C: \(6\times1 = 6\)
• H: \(6\times2 = 12\)
• O: \(6\times2 + 6\times1 = 18\)

Step2: Count C, H, O in glucose

Glucose: \(C_6H_{12}O_6\)

• C: 6
• H: 12
• O: 6

Step3: Find missing O atoms

Missing O: \(18 - 6 = 12\) (so 12 O atoms, as \(6O_2\) has \(6\times2 = 12\) O atoms). Check options: 12 oxygen atoms matches.

Answer:

12 oxygen atoms (the option with "12 oxygen atoms")