Question

the percent of college students marijuana use for a sample of 97,506 students is shown in the accompanying pie chart. find the probability of each event listed in parts (a) through (d) below. click the icon to view the pie chart. (a) randomly selecting a student who never used marijuana the probability is 51.7%. (round to one decimal place as needed.) (b) randomly selecting a student who used marijuana the probability is □%. (round to one decimal place as needed.)

Explanation:

Step1: Use the probability formula

The sum of all probabilities in a sample space is \(100\%\). Let \(P(\text{never used})\) be the probability of selecting a student who never used marijuana and \(P(\text{used})\) be the probability of selecting a student who used marijuana. Then \(P(\text{used})=100\% - P(\text{never used})\).

Step2: Substitute the given value

We know that \(P(\text{never used}) = 51.7\%\). So \(P(\text{used})=100\% - 51.7\%\).

$$P(\text{used})=(100 - 51.7)\%=48.3\%$$

Answer:

\(48.3\)