Question

1. in pea plants, tall plants are dominant over short plants. if a heterozygous plant was crossed with a homozygous recessive plant, what percent of the offspring would have each phenotype? show your work.

Explanation:

Step1: Determine the genotypes of the parents

A heterozygous plant has the genotype \(Pp\) (where \(P\) is the dominant allele for tall and \(p\) is the recessive allele for short). A homozygous recessive plant has the genotype \(pp\).

Step2: Set up the Punnett square

	\(P\)	\(p\)
\(p\)	\(Pp\) (tall)	\(pp\) (short)

Step3: Calculate the phenotypic ratios

Out of the 4 possible offspring in the Punnett square, 2 have the genotype \(Pp\) (tall phenotype) and 2 have the genotype \(pp\) (short phenotype).
The percentage of tall (\(Pp\)): \(\frac{2}{4}\times100\% = 50\%\)
The percentage of short (\(pp\)): \(\frac{2}{4}\times100\%=50\%\)

Answer:

50% of the offspring would have the tall phenotype (\(Pp\)) and 50% would have the short phenotype (\(pp\))