Question

d. parts of an electrochemical cell

in an electrochemical cell, an oxidation-reduction reaction produces electrical energy. identify the labeled parts of the cell that is shown in the figure by writing the corresponding letters into the blanks below. the reaction that is taking place is:
\\ \text{zn(s)} + \text{cu}^{2+}\text{(aq)} \
ightarrow \text{zn}^{2+}\text{(aq)} + \text{cu(s)} \\

voltmeter _______
salt bridge _______
anode _______
cathode _______
solution of copper(ii) _______
solution of zinc(ii) _______
external wire _______

Explanation:

<pre_analysis>
{
"quality": "clear",
"question_count": 1,
"skills_matched": [
"step_cot",
"blank_filling_formatter",
"explain_then_answer",
"tutor",
"mastery_adaptive_brevity"
],
"needs_drawing": false,
"concepts_used": [
"Voltaic Cell Design",
"Electrode Signs"
],
"new_concepts": [
"Galvanic Cell Anatomy"
],
"current_concepts": [
"Voltaic Cell Design",
"Electrode Signs",
"Galvanic Cell Anatomy"
]
}
</pre_analysis>

<reasoning>

Identify the electron flow and electrodes

Using the Voltaic Cell Design and Electrode Signs knowledge points
The reaction is:
\[ \text{Zn(s)} + \text{Cu}^{2+}\text{(aq)}
ightarrow \text{Zn}^{2+}\text{(aq)} + \text{Cu(s)} \]

• Zinc is oxidized: \(\text{Zn(s)}

ightarrow \text{Zn}^{2+}\text{(aq)} + 2\text{e}^-\) (Anode, electrode A).

• Copper is reduced: \(\text{Cu}^{2+}\text{(aq)} + 2\text{e}^-

ightarrow \text{Cu(s)}\) (Cathode, electrode E).

• Electrons flow from anode (A) to cathode (E).

Identify the solutions and salt bridge

Using the Voltaic Cell Design knowledge point

• Solution B contains zinc ions: \(\text{Zn(II)}\) solution.
• Solution D contains copper ions: \(\text{Cu(II)}\) solution.
• Tube C connects the two half-cells: Salt bridge.

Identify the external circuit components

Using the Voltaic Cell Design knowledge point

• Component G measures voltage: Voltmeter.
• Component F is the wire connecting the electrodes: External wire.

</reasoning>

<answer>
In an electrochemical cell, an oxidation-reduction reaction produces electrical energy. Identify the labeled parts of the cell that is shown in the figure by writing the corresponding letters into the blanks below. The reaction that is taking place is:
\[ \text{Zn(s)} + \text{Cu}^{2+}\text{(aq)}
ightarrow \text{Zn}^{2+}\text{(aq)} + \text{Cu(s)} \]

Voltmeter: <blank>G</blank>
Salt bridge: <blank>C</blank>
Anode: <blank>A</blank>
Cathode: <blank>E</blank>
Solution of copper(II): <blank>D</blank>
Solution of zinc(II): <blank>B</blank>
External wire: <blank>F</blank>
</answer>

<post_analysis>
{
"subject": "Natural Science",
"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Natural Science",
"Chemistry",
"Voltaic Cell Design"
]
}
</post_analysis>

Answer:

<pre_analysis>
{
"quality": "clear",
"question_count": 1,
"skills_matched": [
"step_cot",
"blank_filling_formatter",
"explain_then_answer",
"tutor",
"mastery_adaptive_brevity"
],
"needs_drawing": false,
"concepts_used": [
"Voltaic Cell Design",
"Electrode Signs"
],
"new_concepts": [
"Galvanic Cell Anatomy"
],
"current_concepts": [
"Voltaic Cell Design",
"Electrode Signs",
"Galvanic Cell Anatomy"
]
}
</pre_analysis>

<reasoning>

Identify the electron flow and electrodes

Using the Voltaic Cell Design and Electrode Signs knowledge points
The reaction is:
\[ \text{Zn(s)} + \text{Cu}^{2+}\text{(aq)}
ightarrow \text{Zn}^{2+}\text{(aq)} + \text{Cu(s)} \]

• Zinc is oxidized: \(\text{Zn(s)}

ightarrow \text{Zn}^{2+}\text{(aq)} + 2\text{e}^-\) (Anode, electrode A).

• Copper is reduced: \(\text{Cu}^{2+}\text{(aq)} + 2\text{e}^-

ightarrow \text{Cu(s)}\) (Cathode, electrode E).

• Electrons flow from anode (A) to cathode (E).

Identify the solutions and salt bridge

Using the Voltaic Cell Design knowledge point

• Solution B contains zinc ions: \(\text{Zn(II)}\) solution.
• Solution D contains copper ions: \(\text{Cu(II)}\) solution.
• Tube C connects the two half-cells: Salt bridge.

Identify the external circuit components

Using the Voltaic Cell Design knowledge point

• Component G measures voltage: Voltmeter.
• Component F is the wire connecting the electrodes: External wire.

</reasoning>

<answer>
In an electrochemical cell, an oxidation-reduction reaction produces electrical energy. Identify the labeled parts of the cell that is shown in the figure by writing the corresponding letters into the blanks below. The reaction that is taking place is:
\[ \text{Zn(s)} + \text{Cu}^{2+}\text{(aq)}
ightarrow \text{Zn}^{2+}\text{(aq)} + \text{Cu(s)} \]

Voltmeter: <blank>G</blank>
Salt bridge: <blank>C</blank>
Anode: <blank>A</blank>
Cathode: <blank>E</blank>
Solution of copper(II): <blank>D</blank>
Solution of zinc(II): <blank>B</blank>
External wire: <blank>F</blank>
</answer>

<post_analysis>
{
"subject": "Natural Science",
"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Natural Science",
"Chemistry",
"Voltaic Cell Design"
]
}
</post_analysis>