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Question
part 1 of 2
a transversal intersects two parallel lines. the measures of a pair of alternate interior angles are 5v and 2w. the measures of a pair of same - side exterior angles are 10w and 5v. what are the values of w and v?
Step1: Recall angle properties
When a transversal intersects two parallel lines, alternate interior angles are equal, and same - side exterior angles are supplementary (their sum is \(180^{\circ}\)). So we have two equations:
- From alternate interior angles: \(5v = 2w\) (Equation 1)
- From same - side exterior angles: \(10w+5v=180\) (Equation 2)
Step2: Substitute Equation 1 into Equation 2
Substitute \(5v = 2w\) into \(10w + 5v=180\). We get \(10w+2w = 180\).
Combine like terms: \(12w=180\).
Step3: Solve for \(w\)
Divide both sides of the equation \(12w = 180\) by 12: \(w=\frac{180}{12}=15\).
Step4: Solve for \(v\)
Substitute \(w = 15\) into Equation 1 (\(5v=2w\)). So \(5v=2\times15 = 30\).
Divide both sides by 5: \(v=\frac{30}{5}=6\).
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\(w = 15\), \(v=6\)