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part a the table shows the diameters of the planets in our solar system…

Question

part a

the table shows the diameters of the planets in our solar system. assume that a basketball whose diameter is 25 centimeters represents the planet jupiter. find the scale (ratio) between jupiter and the basketball. then use this ratio to find the scaled diameter of the other planets. enter these numbers into the table. (saturn has been done for you.) finally, choose a real-world spherical or nearly spherical object that matches the scaled diameter of each planet.

saturn is shown as an example. to find what saturns size would be after adjusting it to scale, follow these steps. let the scaled diameter of saturn be \\(d\\) centimeters. if jupiters diameter, 142,984 kilometers, is scaled to 25 centimeters, saturns diameter of 120,536 kilometers will be scaled to about 21 centimeters:

\\\frac{142,984}{25} = \frac{120,536}{d}\\
\\d = \frac{120,536 \times 25}{142,984}\\
\\d \approx 21\text{ cm}\\

use this process to complete the table.

mercuryvenusearthmarsjupitersaturnuranusneptune
scaled diameter (cm)2521
spherical objectbasketballdeflated basketball

Explanation:

Response

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"Scientific Modeling",
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<reasoning>

Calculate the scaling ratio

We are given that Jupiter's actual diameter is \(142,984\text{ km}\) and its scaled diameter is \(25\text{ cm}\).
The scaling ratio \(k\) is:
\[k = \frac{25}{142,984}\text{ cm/km}\]

Calculate scaled diameters

Using Scientific Modeling, we scale each planet's diameter \(D\) using the formula \(d = D \times \frac{25}{142,984}\):

  • Mercury: \(4,879 \times \frac{25}{142,984} \approx 0.85\text{ cm}\) (rounds to \(0.9\text{ cm}\) or \(0.85\text{ cm}\))
  • Venus: \(12,104 \times \frac{25}{142,984} \approx 2.12\text{ cm}\) (rounds to \(2.1\text{ cm}\))
  • Earth: \(12,756 \times \frac{25}{142,984} \approx 2.23\text{ cm}\) (rounds to \(2.2\text{ cm}\))
  • Mars: \(6,792 \times \frac{25}{142,984} \approx 1.19\text{ cm}\) (rounds to \(1.2\text{ cm}\))
  • Uranus: \(51,118 \times \frac{25}{142,984} \approx 8.94\text{ cm}\) (rounds to \(8.9\text{ cm}\))
  • Neptune: \(49,528 \times \frac{25}{142,984} \approx 8.66\text{ cm}\) (rounds to \(8.7\text{ cm}\))

Select matching spherical objects

We choose real-world spherical objects that match these scaled diameters:

  • Mercury (\(\approx 0.9\text{ cm}\)): Peppercorn or small blueberry
  • Venus (\(\approx 2.1\text{ cm}\)): Nickel or grape
  • Earth (\(\approx 2.2\text{ cm}\)): Nickel or cherry
  • Mars (\(\approx 1.2\text{ cm}\)): Blueberry or marble
  • Uranus (\(\approx 8.9\text{ cm}\)): Baseball or tennis ball
  • Neptune (\(\approx 8.7\text{ cm}\)): Baseball or tennis ball

</reasoning>

<answer>

PlanetMercuryVenusEarthMarsJupiterSaturnUranusNeptune
Scaled diameter (cm)0.92.12.21.225218.98.7
Spherical objectpeppercorngrapenickelblueberrybasketballdeflated basketballbaseballtennis ball

</answer>

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"Natural Science",
"Solar System Structure",
"Scientific Modeling"
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</post_analysis>

Answer:

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"Solar System Structure",
"Scientific Modeling",
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</pre_analysis>

<reasoning>

Calculate the scaling ratio

We are given that Jupiter's actual diameter is \(142,984\text{ km}\) and its scaled diameter is \(25\text{ cm}\).
The scaling ratio \(k\) is:
\[k = \frac{25}{142,984}\text{ cm/km}\]

Calculate scaled diameters

Using Scientific Modeling, we scale each planet's diameter \(D\) using the formula \(d = D \times \frac{25}{142,984}\):

  • Mercury: \(4,879 \times \frac{25}{142,984} \approx 0.85\text{ cm}\) (rounds to \(0.9\text{ cm}\) or \(0.85\text{ cm}\))
  • Venus: \(12,104 \times \frac{25}{142,984} \approx 2.12\text{ cm}\) (rounds to \(2.1\text{ cm}\))
  • Earth: \(12,756 \times \frac{25}{142,984} \approx 2.23\text{ cm}\) (rounds to \(2.2\text{ cm}\))
  • Mars: \(6,792 \times \frac{25}{142,984} \approx 1.19\text{ cm}\) (rounds to \(1.2\text{ cm}\))
  • Uranus: \(51,118 \times \frac{25}{142,984} \approx 8.94\text{ cm}\) (rounds to \(8.9\text{ cm}\))
  • Neptune: \(49,528 \times \frac{25}{142,984} \approx 8.66\text{ cm}\) (rounds to \(8.7\text{ cm}\))

Select matching spherical objects

We choose real-world spherical objects that match these scaled diameters:

  • Mercury (\(\approx 0.9\text{ cm}\)): Peppercorn or small blueberry
  • Venus (\(\approx 2.1\text{ cm}\)): Nickel or grape
  • Earth (\(\approx 2.2\text{ cm}\)): Nickel or cherry
  • Mars (\(\approx 1.2\text{ cm}\)): Blueberry or marble
  • Uranus (\(\approx 8.9\text{ cm}\)): Baseball or tennis ball
  • Neptune (\(\approx 8.7\text{ cm}\)): Baseball or tennis ball

</reasoning>

<answer>

PlanetMercuryVenusEarthMarsJupiterSaturnUranusNeptune
Scaled diameter (cm)0.92.12.21.225218.98.7
Spherical objectpeppercorngrapenickelblueberrybasketballdeflated basketballbaseballtennis ball

</answer>

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"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Natural Science",
"Solar System Structure",
"Scientific Modeling"
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</post_analysis>