Question

part 1 of 2
the perimeter of the triangle is ( 9sqrt{6} ) cm.
part: 1 / 2
part 2 of 2
the perimeter of the triangle is approximately (square) cm.

Explanation:

Step1: Calculate the value of $\sqrt{6}$

We know that $\sqrt{6}\approx2.45$

Step2: Multiply the value of $\sqrt{6}$ by 9

Since the perimeter is $9\sqrt{6}$, substituting the approximate value of $\sqrt{6}$ we get $9\times2.45 = 22.05$

Answer:

$22.05$