Question

in this part of the experiment, you will be changing the speed of the bottle by dropping it from different heights. you will use the same mass, 0.250 kg, for each trial, so record this mass in table b for each velocity. then calculate the expected kinetic energy (ke) at velocity. use the formula ( ke = \frac{1}{2}mv^2 ), where m is the mass and v is the speed. rec calculations in table b of your student guide. when the speed of the bottle is 2 m/s, the ke is dropdown kg·m²/s². when the speed of the bottle is 3 m/s, the ke is text cut off bottle is 4 m/s, the ke is text cut off bottle is 5 m/s, the ke is text cut off bottle is 6 m/s, the ke is text cut off. the dropdown has options 0.2, 0.5, 1, 2.

Explanation:

Step1: Identify given values

Mass \( m = 0.250 \, \text{kg} \), speed \( v = 2 \, \text{m/s} \), formula \( KE=\frac{1}{2}mv^2 \).

Step2: Substitute values into formula

\( KE=\frac{1}{2} \times 0.250 \times (2)^2 \)

Step3: Calculate step by step

First, \( (2)^2 = 4 \). Then, \( \frac{1}{2} \times 0.250 = 0.125 \). Finally, \( 0.125 \times 4 = 0.5 \).

Answer:

0.5