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Question
opposite sides of a parallelogram are parallel. prove that opposite angles of a parallelogram are congruent. given: ( abcd ) is a parallelogram. prove: ( angle a cong angle c ), ( angle b cong angle d ). diagram of parallelogram ( abcd ) with vertices ( a, b, c, d ). steps: 2) ( mangle a + mangle d = 180 ) 3) ( bc parallel ad ) 4) ( mangle a + mangle b = 180 ); ( mangle c + mangle d = 180 ) 5) ( mangle a + mangle b = mangle b + mangle c ) 6) blank. reasons (right): 3) definition of parallelogram 4) same side interior angles postulate
Step1: Analyze Step 5
We have \( m\angle A + m\angle B = m\angle B + m\angle C \). To show \( \angle A \cong \angle C \), we can use the Subtraction Property of Equality. Subtract \( m\angle B \) from both sides of the equation.
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Since the measures of \( \angle A \) and \( \angle C \) are equal, \( \angle A \cong \angle C \) (by the definition of congruent angles: if two angles have equal measures, they are congruent).
Step2: Prove \( \angle B \cong \angle D \)
Similarly, from the equations \( m\angle A + m\angle D = 180^\circ \) (from same - side interior angles, since \( AB\parallel CD \)) and \( m\angle A + m\angle B = 180^\circ \) (from same - side interior angles, since \( AD\parallel BC \)), we can set \( m\angle A + m\angle D=m\angle A + m\angle B \). Then, by the Subtraction Property of Equality (subtract \( m\angle A \) from both sides), we get \( m\angle D = m\angle B \), so \( \angle B\cong\angle D \).
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To fill in step 5's reason (for showing \( \angle A\cong\angle C \)): Subtraction Property of Equality (and for \( \angle B\cong\angle D \) similarly). The key step for \( \angle A\cong\angle C \) is using the Subtraction Property of Equality on \( m\angle A + m\angle B = m\angle B + m\angle C \) to get \( m\angle A=m\angle C \), hence \( \angle A\cong\angle C \), and similarly for \( \angle B\cong\angle D \).