Question

one professional basketball player typically attempts eight free throws per game. let x represent the number of freethrows made out of eight. the distribution for x is shown in the table.

what is the probability that the basketball player will make at least six free throws out of the eight attempts?
0.11
0.21
0.30
0.32

Explanation:

Step1: Understand the meaning of "at least six"

"At least six" means \(X = 6\), \(X = 7\), or \(X = 8\).

Step2: Sum the corresponding probabilities

We use the formula \(P(X\geq6)=P(X = 6)+P(X = 7)+P(X = 8)\).
Substitute the values from the table: \(P(X = 6)=0.21\), \(P(X = 7)=0.09\), \(P(X = 8)=0.02\).
Then \(P(X\geq6)=0.21 + 0.09+0.02\).

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Answer:

0.32