Question

1. if one of the components in branch 1 is shorted, what would be measured across the good component?

0 volts
minimum current
the applied voltage
infinite ohms

Explanation:

Step1: Understand short - circuit property

A short - circuit has \(R = 0\). In a series circuit (components in branch 1 are in series), \(V=IR\).

Step2: Analyze voltage across good component

If one component in branch 1 is shorted (\(R_{short}=0\)), and assume the current in the branch is \(I\). For the good component, if we consider the two - component series in branch 1 (before shorting, \(V = V_1+V_2\), after shorting one, say component 2 is shorted (\(V_2 = 0\) since \(R_2=0\) and \(V = IR\)). The voltage across the good component (component 1) is \(V_1=I\times R_1\), but in a short - circuited branch (because one component is shorted), the resistance of the branch is dominated by the short. In a parallel - like situation (branches are parallel to the source in a sense, but focusing on the branch internal series), the current will take the path of least resistance (the short). The voltage across the good component (which is in series with the short) is \(V = IR\), and since the short has \(R = 0\) (ideally), the voltage across the non - shorted (good) component (which is in series with the short) is \(0\) volts.

Answer:

A. 0 volts