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in one common system for finding a grade - point average, or gpa, $a = …

Question

in one common system for finding a grade - point average, or gpa,
$a = 4,b = 3,c = 2,d = 1,f = 0$.
the gpa is calculated by multiplying the number of credit hours for a course and the
number assigned to each grade, and then adding these products. then divide this sum by
the total number of credit hours. because each course grade is weighted according to the
number of credits of the course, gpa is called a weighted mean. calculate the gpa for
this transcript
the grade point average is
(round to the nearest hundredth as needed.)

Explanation:

Step1: Calculate the sum of products

Multiply each grade - point by its credit hours and sum them.
For the first B (grade - point \(3\)) with \(4\) credit hours: \(3\times4 = 12\)
For the second B (grade - point \(3\)) with \(2\) credit hours: \(3\times2=6\)
For the third B (grade - point \(3\)) with \(4\) credit hours: \(3\times4 = 12\)
For the C (grade - point \(2\)) with \(4\) credit hours: \(2\times4=8\)
The sum of products \(S=12 + 6+12 + 8=38\)

Step2: Calculate the total credit hours

Sum up all the credit hours. \(4 + 2+4 + 4=14\)

Step3: Calculate the GPA

Divide the sum of products by the total credit hours. \(GPA=\frac{38}{14}\approx2.71\)

Answer:

\(2.71\)