Question

one angle of a right triangle has a measure of ( k^{circ} ), where ( cos (k^{circ})=\frac{1}{4} ). what is ( sin (90^{circ}-k^{circ}) )?

Explanation:

Step1: Use co - function identity

In a right - triangle, for any acute angle \(k\), the co - function identity states that \(\sin(90^{\circ}-k)=\cos(k)\).

Step2: Substitute the given value of \(\cos(k)\)

We are given that \(\cos(k)=\frac{1}{4}\).

Answer:

\(\frac{1}{4}\)