Question

one angle of an isosceles triangle measures 108°. what measures are possible for the other two angles? choose all that apply. 77° 108° 16° 36°

Explanation:

Step1: Determine if \(108^{\circ}\) is the vertex angle

In an isosceles triangle, the sum of angles is \(180^{\circ}\). If \(108^{\circ}\) is the vertex angle, let the base angles be \(x\). Then \(2x + 108^{\circ}=180^{\circ}\).

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Step2: Check if \(108^{\circ}\) can be a base angle

Since \(108^{\circ}+108^{\circ}=216^{\circ}>180^{\circ}\), \(108^{\circ}\) cannot be a base angle.

Answer:

\(36^{\circ}\)