Question

ometry sem a geometry
congruence: sss and hl
point h is the midpoint of side fk.
for the triangles to be congruent by sss, what must be the value of x?

Explanation:

Step1: Set up the equation

Since the triangles are congruent by SSS (Side - Side - Side), the corresponding sides are equal. So, \(3x - 2=2x + 4\).

Step2: Solve the equation for \(x\)

Subtract \(2x\) from both sides: \(3x-2x - 2=2x-2x + 4\), which simplifies to \(x-2 = 4\).
Then add 2 to both sides: \(x-2 + 2=4 + 2\).

Answer:

\(x = 6\)