Question

an old truck compresses a spring scale at the junkyard by 25 cm. the spring constant for the industrial scale at the junkyard is 39,200 n/m. what is the force applied to the scale by the car?

□ n

Explanation:

Step1: Convert compression to meters

The compression \( x \) is 25 cm. Since 1 m = 100 cm, we convert: \( x = \frac{25}{100} = 0.25 \, \text{m} \)

Step2: Use Hooke's Law \( F = kx \)

Hooke's Law states the force \( F \) exerted by a spring is \( F = kx \), where \( k \) is the spring constant and \( x \) is the displacement. Here, \( k = 39200 \, \text{N/m} \) and \( x = 0.25 \, \text{m} \). So, \( F = 39200 \times 0.25 \)

Step3: Calculate the force

\( 39200 \times 0.25 = 9800 \, \text{N} \)

Answer:

9800