Question

an object is launched horizontally from a cliff. if the object lands 10 m from the base of the cliff after a flight of 2 s, what was the objects initial horizontal velocity? 20 m/s 10 m/s 2 m/s 5 m/s

Explanation:

Step1: Recall velocity - distance - time formula

The formula for velocity is $v=\frac{d}{t}$, where $v$ is velocity, $d$ is distance, and $t$ is time.

Step2: Identify values of $d$ and $t$

The horizontal - distance $d = 10$ m and the time of flight $t=2$ s.

Step3: Calculate the initial horizontal velocity

Substitute $d = 10$ m and $t = 2$ s into the formula $v=\frac{d}{t}$, we get $v=\frac{10}{2}=5$ m/s.

Answer:

D. 5 m/s