Question

newtons.
remember to use -10.0 m/s^2 for the acceleration due to gravity
be sure your answer has the appropriate number of significant figures, include correct
units: m, s, m/s, m/s^2, and put a space in between the number & units (example: -10.0
m/s^2).
\\(\vec{f}_g = m\vec{a}_g\\)
mass:50 kg
weight:110 lbs
mass: 50 kg
weight: 42 lbs
earth
mars
your answer

Explanation:

Step1: Identify the formula and values

The formula for gravitational force is \( \vec{F}_g = m\vec{a}_g \). Here, the mass \( m = 50 \, \text{kg} \) and the acceleration due to gravity \( a_g=- 10.0 \, \text{m/s}^2 \) (the negative sign indicates the direction is downward).

Step2: Substitute the values into the formula

Substitute \( m = 50 \, \text{kg} \) and \( a_g=-10.0 \, \text{m/s}^2 \) into \( F_g=ma_g \). So \( F_g = 50\,\text{kg}\times(- 10.0\,\text{m/s}^2) \).

Step3: Calculate the result

\( 50\times(- 10.0)=- 500 \), and the units are \( \text{kg}\cdot\text{m/s}^2 \) which is equivalent to Newtons (N). So \( F_g=- 500 \, \text{N} \) (the negative sign shows the direction is downward, but if we consider the magnitude for weight in the context of the problem's instruction about significant figures and units, we can also present it as \( - 5.0\times10^{2}\, \text{N} \) or just \( - 500 \, \text{N} \) with appropriate significant figures. Since the given values (mass 50 kg - two significant figures? Wait, 50 kg could be one or two significant figures, but the acceleration is given as - 10.0 m/s² (three significant figures). But the mass is 50 kg (maybe two significant figures if the zero is significant, or one if not. But following the example, we can compute as \( 50\times(-10.0)=-500 \) with units.

Answer:

-500 N