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newtons first law quick check a runner exerting a running force of 325 …

Question

newtons first law quick check
a runner exerting a running force of 325 n to the right is met with an air resistance force of 45 n to the left. what is the net force of the runner? (1 point)
280 n
370 n
45 n
325 n

Explanation:

Step1: Define positive and negative directions

Let the right - direction be positive. So, the running force \(F_{1}=+ 325\space N\), and the air - resistance force \(F_{2}=-45\space N\)

Step2: Calculate the net force

The net force \(F_{net}=F_{1}+F_{2}\)
Substitute the values: \(F_{net}=325+( - 45)\)
\(F_{net}=325 - 45\)
\(F_{net}=280\space N\)

Answer:

280 N