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1. newton’s second law of motion states that the force applied to an ob…

Question

  1. newton’s second law of motion states that the force applied to an object is the product of its mass and its acceleration, ( f = m cdot a ). write an equation for the object’s acceleration, given the force and the mass.
  1. solve for ( w ) in terms of ( a, k, ) and ( t ).

( k = a + 3w - t )

  1. a cylinder has a volume of ( 96pi ) ( \text{in}^3 ) and a radius of 4 inches. what is the height of the cylinder?

(hint: the volume of a cylinder is given by ( v = pi r^2 h ).)

Explanation:

Response
Question 1

Step1: Start with the formula \( F = m \cdot a \)

We need to solve for \( a \), so we divide both sides of the equation by \( m \) (assuming \( m
eq 0 \)).

Step2: Divide both sides by \( m \)

\( \frac{F}{m} = \frac{m \cdot a}{m} \)
Simplifying the right - hand side, the \( m \) in the numerator and denominator cancels out, leaving us with \( a=\frac{F}{m} \)

Step1: Start with the equation \( k=a + 3w-t \)

We want to isolate the term with \( w \). First, add \( t \) to both sides of the equation.
\( k + t=a + 3w-t + t \)
Simplifying the right - hand side, the \( -t \) and \( +t \) cancel out, giving \( k + t=a + 3w \)

Step2: Subtract \( a \) from both sides

\( k + t-a=a + 3w-a \)
Simplifying the right - hand side, the \( a \) and \( -a \) cancel out, resulting in \( k + t - a=3w \)

Step3: Divide both sides by 3

\( \frac{k + t - a}{3}=\frac{3w}{3} \)
Simplifying the right - hand side, we get \( w=\frac{k + t - a}{3} \)

Step1: Recall the volume formula for a cylinder \( V=\pi r^{2}h \)

We know that \( V = 96\pi \) and \( r = 4 \). Substitute these values into the formula.
\( 96\pi=\pi\times(4)^{2}\times h \)

Step2: Simplify the right - hand side

First, calculate \( (4)^{2}=16 \), so the equation becomes \( 96\pi=\pi\times16\times h \), or \( 96\pi = 16\pi h \)

Step3: Solve for \( h \)

Divide both sides of the equation by \( 16\pi \) (assuming \( \pi
eq0 \) and \( 16
eq0 \))
\( \frac{96\pi}{16\pi}=\frac{16\pi h}{16\pi} \)
Simplifying the left - hand side, \( \frac{96\pi}{16\pi}=\frac{96}{16}=6 \), and the right - hand side simplifies to \( h \)

Answer:

\( a = \frac{F}{m} \)

Question 2