Question

name: lubin - son saron
period 2
(1)
① find c if it is rotated 270° clockwise
② find h if it is rotated 90° counter - clockwise
c ( ) h ( ) x ( ) h ( )
triangle ohx

Explanation:

Step1: Recall rotation rules

For a 270 - degree clock - wise rotation (which is equivalent to a 90 - degree counter - clockwise rotation), the transformation rule for a point $(x,y)$ in the coordinate plane is $(x,y)\to(y, - x)$. For a 90 - degree counter - clockwise rotation, the rule is $(x,y)\to(-y,x)$. However, since no coordinates of points $C$ and $H$ are given, assume the general rules.

Step2: Apply rotation rules

a) When rotating a point 270 degrees clockwise (or 90 degrees counter - clockwise), if the original coordinates of point $C$ are $(x_C,y_C)$, then the coordinates of $C'$ are $(y_C,-x_C)$.
b) When rotating a point 90 degrees counter - clockwise, if the original coordinates of point $H$ are $(x_H,y_H)$, then the coordinates of $H'$ are $(-y_H,x_H)$.

Answer:

a) If the coordinates of $C$ are $(x,y)$, the coordinates of $C'$ are $(y, - x)$.
b) If the coordinates of $H$ are $(x,y)$, the coordinates of $H'$ are $(-y,x)$.