Question

name: keydan quirino date: 12-22-25 class 601 unit 3 hw #2

1. jada and lin were on bicycles. jada traveled 18 meters in 4 seconds. lin traveled 33 meters in 6 seconds. who was moving faster? explain your reasoning.

Explanation:

Step1: Calculate Jada's speed

Speed is calculated by the formula \( \text{speed} = \frac{\text{distance}}{\text{time}} \). For Jada, distance is 18 meters and time is 4 seconds. So her speed is \( \frac{18}{4} = 4.5 \) meters per second.

Step2: Calculate Lin's speed

For Lin, distance is 33 meters and time is 6 seconds. Using the same speed formula, her speed is \( \frac{33}{6} = 5.5 \) meters per second.

Step3: Compare the speeds

Now we compare 4.5 m/s (Jada's speed) and 5.5 m/s (Lin's speed). Since \( 5.5>4.5 \), Lin's speed is greater.

Answer:

Lin was moving faster because Jada's speed was \( \frac{18}{4}=4.5 \) meters per second and Lin's speed was \( \frac{33}{6} = 5.5 \) meters per second, and \( 5.5>4.5 \).