Question

name: eriliany u. echavar class: verma date: 10 - 08 - 2025 1. $\frac{2x}{2}=5$ 2. $\frac{4x}{5}=2$ 3. $\frac{7x}{3}=7$ 4. $\frac{3x}{4}=6$ 5. $\frac{10x}{4}=3$

Explanation:

Step1: Isolate x in each equation

For the equation $\frac{2x}{2}=5$, the 2s in the numerator and denominator on the left - hand side cancel out, leaving $x = 5$.
For $\frac{4x}{5}=2$, multiply both sides by 5 to get $4x=10$, then divide both sides by 4, so $x=\frac{10}{4}=\frac{5}{2}$.
For $\frac{7x}{3}=7$, multiply both sides by 3 to get $7x = 21$, then divide both sides by 7, so $x = 3$.
For $\frac{3x}{4}=6$, multiply both sides by 4 to get $3x=24$, then divide both sides by 3, so $x = 8$.
For $\frac{10x}{4}=3$, multiply both sides by 4 to get $10x = 12$, then divide both sides by 10, so $x=\frac{12}{10}=\frac{6}{5}$.

Answer:

1. $x = 5$
2. $x=\frac{5}{2}$
3. $x = 3$
4. $x = 8$
5. $x=\frac{6}{5}$