Question

multiple choice 1 point
one parent has brown eyes (bb) and has offspring with another parent who has blue eyes (bb). what is the probability that one of their children will have blue eyes?
○ 0%
○ 25%
○ 50%
○ 75%
○ 100%
clear my selection

Explanation:

Step1: Determine Genotypes of Parents

One parent is \( BB \) (brown eyes, homozygous dominant), the other is \( bb \) (blue eyes, homozygous recessive).

Step2: Analyze Gamete Production

• Parent \( BB \) can only produce \( B \) gametes.
• Parent \( bb \) can only produce \( b \) gametes.

Step3: Determine Offspring Genotypes

When crossing \( BB \times bb \), all offspring will have the genotype \( Bb \) (since each offspring gets one \( B \) from the first parent and one \( b \) from the second parent).

Step4: Relate Genotype to Phenotype

The genotype \( Bb \) results in brown eyes (as \( B \) is dominant over \( b \)). Blue eyes require the genotype \( bb \). Since no offspring will have \( bb \), the probability of a child having blue eyes is \( 0\% \).

Answer:

0% (the option corresponding to 0%)