Question

ms. florina buys a bag of different - colored rubber bands. she randomly selects a rubber band, records the color, and returns it to the bag. she does this a total of 50 times and selects 8 red, 18 blue, 10 green, and 14 yellow rubber bands. based on this information, what is the probability that ms. florina will select a blue rubber band, return it to the bag, and then select a green rubber band? click the arrows to choose an answer from each menu. based on the given information, the probablity that ms. florina will select a blue rubber band is choose... and the probability that she will select a green rubber band is choose... the probability that she will select a blue rubber band, return it to the bag, and then select a green rubber band is choose...

Explanation:

Step1: Calculate P(blue)

Probability = favorable/total trials. Blue count=18, total=50.
$P(\text{blue}) = \frac{18}{50} = \frac{9}{25}$

Step2: Calculate P(green)

Green count=10, total=50.
$P(\text{green}) = \frac{10}{50} = \frac{1}{5}$

Step3: Calculate combined probability

Independent events: multiply probabilities.
$P(\text{blue then green}) = \frac{9}{25} \times \frac{1}{5} = \frac{9}{125}$

Answer:

Probability of blue: $\frac{9}{25}$
Probability of green: $\frac{1}{5}$
Probability of blue then green: $\frac{9}{125}$