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a movie theater had 1,200 visitors last month, and 1,320 visitors this …

Question

a movie theater had 1,200 visitors last month, and 1,320 visitors this month. what was the percent increase in the number of visitors?
write an equation that represents this situation. let p represent the percent.
visitors: 0 1200 1320
0% 100% p

Explanation:

Step1: Understand Percent Increase

Percent increase formula: New = Old + (Old * Percent). Here, old = 1200, new = 1320, percent = \( \frac{p}{100} \) (since p is percent).

Step2: Form Equation

Substitute values: \( 1200 + 1200 \times \frac{p}{100} = 1320 \). Simplify \( 1200 \times \frac{p}{100} \) to \( 12p \), so equation is \( 1200 + 12p = 1320 \), or factor 1200: \( 1200(1 + \frac{p}{100}) = 1320 \). Using the given boxes, structure as \( 1200 + 1200 \times \frac{p}{100} = 1320 \), but with the provided numbers, the equation is \( 1200 + 1200 \times \frac{p}{100} = 1320 \), which can be written as \( 1200 + 12p = 1320 \), but using the given options (1200, +, 1200(p/100), 1320), so the equation is \( 1200 + 1200 \times \frac{p}{100} = 1320 \), or with the boxes: \( 1200 + 1200 \times \frac{p}{100} = 1320 \) (using 1200, +, 1200(p/100), 1320 from the options).

Answer:

\( 1200 + 1200 \times \frac{p}{100} = 1320 \) (or in the boxed form with the given numbers: \( 1200 + 1200 \times \frac{p}{100} = 1320 \), using the numbers 1200, +, \( 1200 \times \frac{p}{100} \), 1320)