QUESTION IMAGE
Question
modeling real life the numbers of text messages sent and received in one day by a random sample of 30 teen cellphone users are shown in the table. number of text messages 35 65 64 88 46 42 71 68 65 97 58 47 52 37 84 58 85 46 56 90 78 76 74 36 74 62 65 75 96 72 estimate the population mean \\( \mu \\). round your answer to the nearest tenth. the population mean \\( \mu \\) is about \\( \square \\).
Step1: Sum all data points
First, we add up all the numbers of text messages. Let's list them out: 35, 65, 64, 88, 46, 42, 71, 68, 65, 97, 58, 47, 52, 37, 84, 58, 85, 46, 56, 90, 78, 76, 74, 36, 74, 62, 65, 75, 96, 72.
Now, let's calculate the sum:
35 + 65 = 100; 100 + 64 = 164; 164 + 88 = 252; 252 + 46 = 298; 298 + 42 = 340; 340 + 71 = 411; 411 + 68 = 479; 479 + 65 = 544; 544 + 97 = 641;
641 + 58 = 700 - 1 (wait, 641 + 58 = 699); 699 + 47 = 746; 746 + 52 = 798; 798 + 37 = 835; 835 + 84 = 919; 919 + 58 = 977; 977 + 85 = 1062; 1062 + 46 = 1108; 1108 + 56 = 1164; 1164 + 90 = 1254;
1254 + 78 = 1332; 1332 + 76 = 1408; 1408 + 74 = 1482; 1482 + 36 = 1518; 1518 + 74 = 1592; 1592 + 62 = 1654; 1654 + 65 = 1719; 1719 + 75 = 1794; 1794 + 96 = 1890; 1890 + 72 = 1962. Wait, maybe a better way: let's count the number of data points, which is 30 (since it's a sample of 30 teens). Wait, let's check the number of numbers: the table has 6 rows, 5 columns each, so 6*5=30. Let's re - calculate the sum carefully:
Let's group them:
First row: 35, 65, 64, 88, 46. Sum: 35 + 65 = 100; 64 + 88 = 152; 46. Total: 100+152 + 46=298.
Second row: 42, 71, 68, 65, 97. Sum: 42+71 = 113; 68+65 = 133; 97. Total: 113+133 + 97=343.
Third row: 58, 47, 52, 37, 84. Sum: 58+47 = 105; 52+37 = 89; 84. Total: 105+89 + 84=278.
Fourth row: 58, 85, 46, 56, 90. Sum: 58+85 = 143; 46+56 = 102; 90. Total: 143+102 + 90=335.
Fifth row: 78, 76, 74, 36, 74. Sum: 78+76 = 154; 74+36 = 110; 74. Total: 154+110 + 74=338.
Sixth row: 62, 65, 75, 96, 72. Sum: 62+65 = 127; 75+96 = 171; 72. Total: 127+171 + 72=370.
Now, sum all these row sums: 298 + 343 = 641; 641+278 = 919; 919+335 = 1254; 1254+338 = 1592; 1592+370 = 1962. So the total sum of all 30 data points is 1962.
Step2: Calculate the mean
The formula for the mean (average) is $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $n$ is the number of data points and $\sum_{i = 1}^{n}x_{i}$ is the sum of the data points. Here, $n = 30$ and $\sum_{i=1}^{30}x_{i}=1962$.
So the mean $\mu\approx\frac{1962}{30}=65.4$. Wait, wait, 1962 divided by 30: 30*65 = 1950, 1962 - 1950 = 12, 12/30 = 0.4, so 65.4? Wait, no, wait, did I calculate the sum correctly? Let's check with another approach. Let's list all numbers and add:
35, 65, 64, 88, 46, 42, 71, 68, 65, 97, 58, 47, 52, 37, 84, 58, 85, 46, 56, 90, 78, 76, 74, 36, 74, 62, 65, 75, 96, 72.
Let's add them one by one:
Start with 0.
0 + 35 = 35
35 + 65 = 100
100 + 64 = 164
164 + 88 = 252
252 + 46 = 298
298 + 42 = 340
340 + 71 = 411
411 + 68 = 479
479 + 65 = 544
544 + 97 = 641
641 + 58 = 699
699 + 47 = 746
746 + 52 = 798
798 + 37 = 835
835 + 84 = 919
919 + 58 = 977
977 + 85 = 1062
1062 + 46 = 1108
1108 + 56 = 1164
1164 + 90 = 1254
1254 + 78 = 1332
1332 + 76 = 1408
1408 + 74 = 1482
1482 + 36 = 1518
1518 + 74 = 1592
1592 + 62 = 1654
1654 + 65 = 1719
1719 + 75 = 1794
1794 + 96 = 1890
1890 + 72 = 1962. Yes, the sum is 1962. Then the mean is 1962 / 30 = 65.4? Wait, no, 30*65 = 1950, 1962 - 1950 = 12, 12/30 = 0.4, so 65.4? Wait, but let's check with a calculator - like approach:
1962 ÷ 30: 30*60 = 1800, 1962 - 1800 = 162, 162 ÷ 30 = 5.4, so 60 + 5.4 = 65.4. Wait, that's correct. Wait, but maybe I made a mistake in the sum? Let's check the number of terms: 30 terms. Let's count:
Row 1: 5 terms (35,65,64,88,46)
Row 2: 5 terms (42,71,68,65,97) - total 10
Row 3: 5 terms (58,47,52,37,84) - total 15
Row 4: 5 terms (58,85,46,56,90) - total 20
Row 5: 5 terms (78,76,74,36,74) - total 25
Row 6: 5 terms (62,65,75,96,72) - total 30. Correct.
So the mean is $\frac{1962}{30}…
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65.4