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mike used the computation \\(\\frac{7}{(6+8+7)} \\approx 0.33 = 33\\%\\…

Question

mike used the computation \\(\frac{7}{(6+8+7)} \approx 0.33 = 33\\%\\) to find the percentage of eighth-grade band members who can play more than one instrument. what error did mike make?

  • mike included 7 when finding a sum to use as the denominator of his fraction.
  • mike used the total of the column containing 7 as his denominator instead of the total of the row containing 7.
  • mike should have used the sum of all the cell values as his denominator.
  • mike should have used the number of eighth-grade students who can only play one instrument as the denominator of his fraction.

Explanation:

Identify the target percentage and correct values

The target is the percentage of eighth-grade band members who can play more than one instrument.

  • Number of eighth-grade band members who can play more than one instrument: \(7\)
  • Total number of eighth-grade band members (the row containing \(7\)): \(18 + 7 = 25\)
  • Correct calculation: \(\frac{7}{25} = 0.28 = 28\%\)

Analyze Mike's calculation and error

  • Mike's calculation: \(\frac{7}{6 + 8 + 7} \approx 0.33 = 33\%\)
  • The denominator used by Mike is \(6 + 8 + 7 = 21\), which is the sum of the column "Can Play More than One Instrument".
  • Therefore, Mike used the total of the column containing \(7\) as his denominator instead of the total of the row containing \(7\).

Answer:

  • Mike included 7 when finding a sum to use as the denominator of his fraction.
  • Mike used the total of the column containing 7 as his denominator instead of the total of the row containing 7. (Correct answer)
  • Mike should have used the sum of all the cell values as his denominator.
  • Mike should have used the number of eighth-grade students who can only play one instrument as the denominator of his fraction.