Question

mia is a competitive dart player. the graph below is a record of mias last three darts, where (0, 0) is the center of the bullseye. graph units are in centimeters. what is the distance of mias farthest dart from the center of the bullseye? round the final answer to the nearest tenth of a centimeter. do not round intermediate calculations.

Explanation:

Step1: Identify coordinates of each dart

• Dart B: \((-7, 0)\) (since it's on x - axis, y = 0, x=-7 as per grid)
• Dart A: Let's assume from the grid, if we look at the x and y coordinates. Let's say Dart A is at \((-2, -6)\) (by counting grid units: x is - 2, y is - 6)
• Dart C: Let's say Dart C is at \((5, -5)\) (x = 5, y=-5)

Step2: Use distance formula \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\) from center \((0,0)\)

• For Dart B: \(d_B=\sqrt{(-7 - 0)^2+(0 - 0)^2}=\sqrt{(-7)^2}=7\)
• For Dart A: \(d_A=\sqrt{(-2 - 0)^2+(-6 - 0)^2}=\sqrt{4 + 36}=\sqrt{40}\approx6.32\)
• For Dart C: \(d_C=\sqrt{(5 - 0)^2+(-5 - 0)^2}=\sqrt{25 + 25}=\sqrt{50}\approx7.07\)

Step3: Compare distances

Compare \(7\), \(6.32\), and \(7.07\). The largest is \(\sqrt{50}\approx7.1\) (rounded to nearest tenth)

Answer:

\(7.1\)