Question

mendels law of segregation
female
gametes
g2
g1
g2
g1
male
gametes
g2
g1
g2
g1
g2
g1
g2
g1
y
y
yy
yy
wy
1/8
1/4
1/2
9/16
3/4
reset
help
3 of 10

Explanation:

Step1: Identify the cross type

The female and male are both heterozygous (Yy), so it's a monohybrid cross (Yy × Yy).

Step2: Recall Mendel's segregation for monohybrid cross

For a Yy × Yy cross, the Punnett square gives genotypes: YY (1/4), Yy (2/4 = 1/2), yy (1/4). Phenotypically, dominant (Y - ) is 3/4 and recessive (yy) is 1/4. But looking at the gametes or the square, if we consider the probability of a single allele or genotype. Wait, maybe the question is about the probability of a gamete? Wait, the female is Yy, so she produces Y and y gametes each with probability 1/2. Similarly, male is Yy, so Y and y each 1/2. But in the Punnett square, each cell is a combination. Wait, maybe the question is about the probability of a genotype? Wait, the options have 1/2, 1/4, etc. Wait, maybe the missing part is to find the probability of a certain genotype or gamete. Wait, the female is Yy, so when producing gametes, the probability of Y or y is 1/2. So if we are filling the gametes, the female gametes: Y and y, each with probability 1/2. Similarly for male. But looking at the squares, maybe the G1 and G2 are alleles. Wait, maybe the question is about the probability of a gamete from Yy, which is 1/2 for Y and 1/2 for y. So the correct probability is 1/2.

Answer:

$\frac{1}{2}$ (or the option with 1/2, depending on the question's context, but based on Mendel's segregation for Yy parent, gamete probability is 1/2)