Question

$x^2 + 49 = 0$

Explanation:

Step1: Isolate \(x^2\)

Subtract 49 from both sides: \(x^2 = - 49\)

Step2: Solve for \(x\)

Take square roots: \(x=\pm\sqrt{-49}\). Since \(\sqrt{-49}=\sqrt{49}\cdot\sqrt{-1} = 7i\), we get \(x = \pm7i\)

Answer:

\(x = \pm7i\)