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Question
$\sqrt{8}$
Step1: Factor the radicand
We can factor 8 as \( 4\times2 \), so \( \sqrt{8}=\sqrt{4\times2} \).
Step2: Use the property of square roots
Using the property \( \sqrt{ab}=\sqrt{a}\times\sqrt{b} \) (where \( a\geq0 \) and \( b\geq0 \)), we get \( \sqrt{4\times2}=\sqrt{4}\times\sqrt{2} \).
Step3: Simplify \( \sqrt{4} \)
Since \( \sqrt{4} = 2 \), then \( \sqrt{4}\times\sqrt{2}=2\sqrt{2} \).
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\( 2\sqrt{2} \)