Question

solve:
$x^2 - 144 = 0$
a. $x = -12, x = 12$
b. $x = -72, x = 72$
c. $x = -144, x = 144$
d. $x = 12, x = 144$

Explanation:

Step1: Isolate \(x^2\)

Add 144 to both sides: \(x^2 = 144\)

Step2: Take square roots

\(x=\pm\sqrt{144}=\pm12\)

Answer:

A. \(x = -12, x = 12\)