Question

solve for p.
$7^p = 7$
$p = \square$

Explanation:

Step1: Recall exponential property

For any non - zero number \(a\), \(a^{x}=a^{y}\) implies \(x = y\) (since the exponential function \(y = a^{x}\) is one - to - one for \(a>0,a
eq1\)).
In the equation \(7^{p}=7\), we can rewrite the right - hand side as \(7^{1}\) (because \(7 = 7^{1}\)).

Step2: Apply the property

Since \(7^{p}=7^{1}\) and the base \(a = 7>0,a
eq1\), by the one - to - one property of exponential functions, we can conclude that \(p = 1\).

Answer:

\(1\)