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solve for g. $d=\\frac{4}{7}(f+g)$ $g=\\square$

Question

solve for g.
$d=\frac{4}{7}(f+g)$
$g=\square$

Explanation:

Step1: Eliminate the fraction

Multiply both sides of the equation \( D = \frac{4}{7}(F + G) \) by \( \frac{7}{4} \) to get rid of the fraction on the right - hand side.

$$ \frac{7}{4}D=\frac{7}{4}\times\frac{4}{7}(F + G) $$

Simplifying the right - hand side, we have \( \frac{7}{4}D=F + G \).

Step2: Solve for G

Subtract \( F \) from both sides of the equation \( \frac{7}{4}D=F + G \) to isolate \( G \).

$$ G=\frac{7}{4}D - F $$

Answer:

\( G=\frac{7}{4}D - F \)