solve for $c$.
\a = \frac{2}{9}(b + c)\
\c = \

Question

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Literal Equations" ], "new_concepts": [], "current_concepts": [ "Literal Equations", "Algebraic Manipulation" ] } ## Multiply both sides by 9 $$ 9A = 2(B + C) $$ ## Divide both sides by 2 $$ \frac{9A}{2} = B + C $$ ## Subtract B from both sides $$ C = \frac{9A}{2} - B $$ Solve for $C$. $A = \frac{2}{9}(B + C)$ $C =$ $\frac{9A}{2} - B$ { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Literal Equations" ] }

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QUESTION IMAGE

Question

Explanation:

Multiply both sides by 9

Divide both sides by 2

Subtract B from both sides

Answer: