Question

simplify.
$y^2 \cdot y^2 \cdot y$

Explanation:

Step1: Recall exponent rule for multiplication

When multiplying exponential expressions with the same base, we add the exponents. The rule is \(a^m \cdot a^n = a^{m + n}\). Also, note that \(y = y^1\).
So, for \(y^2 \cdot y^2 \cdot y\), we can rewrite \(y\) as \(y^1\), then we have \(y^2 \cdot y^2 \cdot y^1\).

Step2: Add the exponents

Now, add the exponents: \(2 + 2 + 1\).
Calculating the sum: \(2+2 = 4\), then \(4 + 1 = 5\).
So, using the exponent rule, \(y^2 \cdot y^2 \cdot y^1 = y^{2 + 2 + 1}=y^5\).

Answer:

\(y^5\)