Question

simplify.
\\(\frac{18y^2 - 48y}{6y^2 - 18y}\\)

Explanation:

Step1: Factor numerator and denominator

Factor out the greatest common factor (GCF) from the numerator \(18y^2 - 48y\) and the denominator \(6y^2 - 18y\).
For the numerator: \(18y^2 - 48y = 6y(3y - 8)\) (since GCF of \(18y^2\) and \(48y\) is \(6y\)).
For the denominator: \(6y^2 - 18y = 6y(y - 3)\) (since GCF of \(6y^2\) and \(18y\) is \(6y\)).

Step2: Simplify the fraction

Now we have the fraction \(\frac{6y(3y - 8)}{6y(y - 3)}\). We can cancel out the common factor \(6y\) (assuming \(y
eq 0\) and \(y
eq 3\) to avoid division by zero).

Answer:

\(\frac{3y - 8}{y - 3}\)