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Question
question 1
- if \\(\frac{2x - 1}{3} = -4x\\), then \\(x = ?\\)
a \\(\frac{1}{3}\\)
b \\(\frac{1}{10}\\)
c \\(\frac{1}{14}\\)
d \\(\frac{1}{24}\\)
Step1: Eliminate the denominator
Multiply both sides of the equation $\frac{2x - 1}{3}=-4x$ by 3 to get rid of the denominator. So we have $3\times\frac{2x - 1}{3}=3\times(-4x)$, which simplifies to $2x - 1=-12x$.
Step2: Move the terms with x to one side
Add $12x$ to both sides of the equation $2x - 1=-12x$. We get $2x+12x - 1=-12x + 12x$, that is $14x-1 = 0$. Then add 1 to both sides: $14x-1 + 1=0 + 1$, so $14x=1$.
Step3: Solve for x
Divide both sides of the equation $14x = 1$ by 14. We have $x=\frac{1}{14}$.
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C. $\frac{1}{14}$