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of $36x - 8y^2$ when $x = 3$ and $y = -6$?

Question

of $36x - 8y^2$ when $x = 3$ and $y = -6$?

Explanation:

Step1: Substitute given values

Substitute $x=3$ and $y=-6$ into $36x - 8y^2$:
$36(3) - 8(-6)^2$

Step2: Calculate exponential term

Compute $(-6)^2$:
$(-6)^2 = 36$

Step3: Perform multiplication operations

Calculate $36(3)$ and $8(36)$:
$36(3) = 108$, $8(36) = 288$

Step4: Subtract the two results

Subtract the second product from the first:
$108 - 288$

Answer:

$-180$