Question

$\frac{3}{4}(x - 2) = -3$

Explanation:

Step1: Eliminate the fraction

Multiply both sides of the equation $\frac{3}{4}(x - 2)=- 3$ by $\frac{4}{3}$ to get rid of the fraction on the left - hand side. According to the property of equality (if $a = b$, then $a\times c=b\times c$ for any non - zero real number $c$), we have:
$\frac{4}{3}\times\frac{3}{4}(x - 2)=\frac{4}{3}\times(-3)$
Simplifying the left - hand side, $\frac{4}{3}\times\frac{3}{4}=1$, so the equation becomes $x - 2=\frac{4\times(-3)}{3}$
Calculate the right - hand side: $\frac{4\times(-3)}{3}=\frac{-12}{3}=-4$
So now the equation is $x - 2=-4$

Step2: Solve for x

Add 2 to both sides of the equation $x - 2=-4$ (using the property of equality: if $a = b$, then $a + c=b + c$).
$x-2 + 2=-4 + 2$
Simplifying both sides, we get $x=-2$

Answer:

$x = - 2$