Question

divide.
$\frac{4\times 10^{-5}}{2\times 10^{-3}}$
$7\times 10^{-8}$ $2\times 10^{1}$ $2\times 10^{-8}$ $2\times 10^{-2}$

Explanation:

Step1: Divide the coefficients

$\frac{4}{2}=2$

Step2: Divide the powers of 10

Using the rule $\frac{a^m}{a^n}=a^{m - n}$, we have $\frac{10^{-5}}{10^{-3}}=10^{-5-(-3)} = 10^{-2}$

Step3: Combine the results

$2\times10^{-2}$

Answer:

$2\times 10^{-2}$