QUESTION IMAGE
Question
d) 8 m 15 m y
Step1: Apply Pythagorean theorem
In a right - triangle, $a^{2}+b^{2}=c^{2}$, where $c$ is the hypotenuse and $a$ and $b$ are the legs. Here, $c = 15$ m, $a = 8$ m, and we want to find $b=y$. So, $y^{2}+8^{2}=15^{2}$.
Step2: Rearrange the equation
$y^{2}=15^{2}-8^{2}$. Calculate $15^{2}=225$ and $8^{2}=64$. Then $y^{2}=225 - 64=161$.
Step3: Solve for $y$
$y=\sqrt{161}\approx 12.7$ m.
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$y=\sqrt{161}\text{ m}\approx12.7\text{ m}$