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Question
- $sqrt{18}=$
Step1: Factorize 18
$18 = 9\times2$
Step2: Apply square - root property
$\sqrt{18}=\sqrt{9\times2}$
Since $\sqrt{ab}=\sqrt{a}\times\sqrt{b}$ ($a = 9$, $b = 2$ and $a\geq0$, $b\geq0$), we have $\sqrt{9\times2}=\sqrt{9}\times\sqrt{2}$
Step3: Calculate $\sqrt{9}$
$\sqrt{9}=3$
So $\sqrt{18}=3\sqrt{2}$
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$3\sqrt{2}$