Question

1. $-3x^{0} \cdot 2x^{-1}y^{5}$

Explanation:

Step1: Simplify $x^0$ rule

Any non-zero number to the 0 power is 1, so $x^0 = 1$.
Expression: $-3 \cdot 1 \cdot 2x^{-1}y^5 = -3 \cdot 2x^{-1}y^5$

Step2: Multiply constant coefficients

Multiply -3 and 2.
Expression: $(-3 \times 2)x^{-1}y^5 = -6x^{-1}y^5$

Step3: Rewrite negative exponent

Use $x^{-n} = \frac{1}{x^n}$ to eliminate negative exponent.
Expression: $-6 \cdot \frac{1}{x} \cdot y^5 = \frac{-6y^5}{x}$

Answer:

$\frac{-6y^5}{x}$ or $-\frac{6y^5}{x}$