Question

1. \\((v - 8) \cdot \dfrac{7v + 49}{v - 8}\\)

Explanation:

Step1: Identify common factor

Notice that \((v - 8)\) is in the numerator (as a factor) and denominator. For \(v
eq8\) (to avoid division by zero), we can cancel \((v - 8)\).

$$ (v - 8)\cdot\frac{7v + 49}{v - 8}=\frac{(v - 8)(7v + 49)}{v - 8} $$

Step2: Cancel common terms

Cancel out the \((v - 8)\) terms (since \(v
eq8\)):

$$ \frac{(v - 8)(7v + 49)}{v - 8}=7v + 49 $$

Answer:

\(7v + 49\) (with the restriction \(v
eq8\))